#### Answer

False. Sample change:
$(-\infty,3) \cup (-\infty,-2) = (-\infty,3)$

#### Work Step by Step

The given statement is:
$(-\infty,3) \cup (-\infty,-2) = (-\infty,-2)$
This statement is false because the union of the two regions goes up to the value $3$, not the value $-2$ (which would be the intersection). We fix the statement as follows:
$(-\infty,3) \cup (-\infty,-2) = (-\infty,3)$